8 solutions

  • 2
    @ 2026-5-27 17:01:55
    #include<bits/stdc++.h>
    using namespace std;
    const int N=1e7+10;
    int n,n2,m2,m,a[N],k;
    signed main(){
    	cin>>n>>n2>>m>>m2;
    	for(int i=n;i<=n2;i++){
    		a[i]++;
    	}for(int i=m;i<=m2;i++){
    		a[i]++;
    	}for(int i=min(n,m);i<=max(n2,m2);i++){
    		if(a[i]==2){
    			k++;
    		}
    	}
    	if(k!=0){
    		cout<<k-1;
    		return 0;
    	}
    	else cout<<k;
    }
    
    

    Information

    ID
    1597
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    7
    Tags
    (None)
    # Submissions
    216
    Accepted
    51
    Uploaded By