10 solutions
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0
Guest MOD
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2
#include<bits/stdc++.h> using namespace std; int main(){ int n,m,s,u,max=0,min=10,sum=0; double mmax=0; int a[21]={0}; cin>>n>>m; for(int i=1;i<=n;i++){ for(int j=1;j<=m;j++){ cin>>s; a[j]=s; if(s>=max) max=s; if(s<=min) min=s; } for(int t=1;t<=m;t++){ sum+=a[t]; } sum=sum-max-min; u=sum/(m-2); if(u>=mmax) mmax=u; max=0; min=10; sum=0; } printf("%.2lf",mmax); return 0; }
Information
- ID
- 1638
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- # Submissions
- 43
- Accepted
- 15
- Uploaded By