3 solutions
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#include<bits/stdc++.h> typedef long long ll; using namespace std; const int N=10010; struct asd{ int number; int price; int price_sum; }; asd a[N]; int s[N]; int n; int sum; int m=1e7; int main(){
cin.sync_with_stdio(false); ios::sync_with_stdio(0); cin.tie(0);cout.tie(0); cin>>n; for(int i=1;i<=3;i++){ cin>>a[i].number>>a[i].price; while(sum*a[i].number<n)sum++; a[i].price_sum=sum*a[i].price; if(m>a[i].price_sum){ m=a[i].price_sum; } sum=0; } cout<<m; return 0;}
Information
- ID
- 402
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 7
- Tags
- (None)
- # Submissions
- 176
- Accepted
- 41
- Uploaded By