3 solutions

  • 0

    #include <iostream

    #include <string

    using namespace std;

    main() {

    int n,a[105],ans;

    char s;

    cin>>n;

    for(int i=0; i<n; i++) {

    cin>>s;

    a[i]=s;

    if(a[i-1]'V'&&a[i]'K')ans++;

    }

    cout<<ans;

    return 0;

    }

    楼下的步骤有点麻烦,我也发一个🎉️

    Information

    ID
    451
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    6
    Tags
    (None)
    # Submissions
    58
    Accepted
    19
    Uploaded By