1 solutions

  • 1
    @ 2025-10-29 17:31:18
    #include <bits/stdc++.h>
    using namespace std;
    int a[100000];
    int n;
    long long cnt1[105],cnt2[105];
    long long cnt0;
    int main(){
    	cin>>n;
    	for(int i=1;i<=n;i++) cin>>a[i];
    	for(int i=1;i<=n;i++){
    		if(a[i]==0) cnt0++;
    		else if(a[i]<0) cnt2[-a[i]]++;
    		else cnt1[a[i]]++;
    	}
    	long long ans=0;
    	ans+=cnt0*(cnt0-1)/2;
    	for(int i=1;i<=100;i++) ans+=cnt1[i]*cnt2[i];
    	cout<<ans;
    	return 0;
    }
    
    
    • 1

    Information

    ID
    610
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    9
    Tags
    (None)
    # Submissions
    197
    Accepted
    19
    Uploaded By