1 solutions

  • 1
    @ 2024-12-2 21:19:21
    #include<bits/stdc++.h>
    typedef long long lll;
    using namespace std;
    typedef double ll;
    const int N=1010;
    lll nums;
    ll s;
    int main(){
    	
    	cin.sync_with_stdio(false);
    	ios::sync_with_stdio(0);
    	cin.tie(0);cout.tie(0);
        cin>>s;
    	for(ll i=0;i<=100;i++){
    		for(ll j=0;j<=100;j++){
    			for(ll k=0;k<=100;k++){
    				for(ll l=0;l<=100;l++){
    					if(abs((100-i)*(100-j)*(100-k)*(100-l)-s*1e8)<1){
    						nums++;
    					}
    				}             	
    			}
    		}
    	}
    
                           
        cout<<nums<<endl;
        return 0;
    }
    
    
    • 1

    Information

    ID
    705
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    7
    Tags
    (None)
    # Submissions
    137
    Accepted
    29
    Uploaded By