#include<bits/stdc++.h> using namespace std; int main() { int a,b,c,d,e,f,g,h; double i; cin>>a>>b>>c>>d; a=a60; c=c60; e=a+b; f=c+d; g=f-e; h=g/60; i=g%60; cout<<h<<" "<<i; return 0; }

#include<bits/stdc++.h>
using namespace std;
int main(){
    int a,b,c,d;cin>>a>>b>>c>>d;
    int x=(c*60+d)-(a*60+b);
    cout<<x/60<<' '<<x%60;
}

#include <bits/stdc++.h> using namespace std; int a,b,c,d,e,f; int main() { cin>> a>> b>> c>> d; e = c - a; if(b<=d){ f = d - b; }else{ e--; f = 60 - (b - d); } cout<< e<< ' '<< f; return 0; }

#include <bits/stdc++.h> #define int long long using namespace std; int n[100],n2,n3; signed main(){ for(int i=1;i<=4;i++){ cin>>n[i]; if(i%2!=0) n[i]*=60; } n2=n[1]+n[2],n3=n[3]+n[4]; n2=n3-n2,n3=n2/60,n2=n2%60; cout<<n3<<" "<<n2<<"\n"; return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ int a,b,c,d,e,f,g,h; double i; cin>>a>>b>>c>>d; a=a60; c=c60; e=a+b; f=c+d; g=f-e; h=g/60; i=g%60; cout<<h<<" "<<i; return 0; }

#include <bits/stdc++.h>
#define int long long 
using namespace std;
int n[100],n2,n3;
signed main(){ 
	for(int i=1;i<=4;i++){
		cin>>n[i];
		if(i%2!=0) n[i]*=60;
	}
	n2=n[1]+n[2],n3=n[3]+n[4];
	n2=n3-n2,n3=n2/60,n2=n2%60;
	cout<<n3<<" "<<n2<<"\n";
	return 0;
}

#include<bits/stdc++.h> using namespace std; int main(){ int a,b,c,d,e,f,g,h; double i; cin>>a>>b>>c>>d; a=a60; c=c60; e=a+b; f=c+d; g=f-e; h=g/60; i=g%60; cout<<h<<" "<<i; return 0; }

好样的！你已经做到这样的题了，相信我，你能自己做出来的！！！